Difference between revisions of "Variance of exponential distribution"

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==Theorem==
<strong>[[Variance of exponential distribution|Theorem]]:</strong> Let $X$ have the [[exponential distribution]] on $\mathbb{T}$. Then,
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If $X$ with a random variable with the [[exponential distribution]] with parameter $\lambda$, then,
$$\mathrm{Var}_{\mathbb{T}}(X)=\dfrac{1}{\lambda^2}.$$
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$$\mathrm{Var}_{\mathbb{T}}(X)=\dfrac{1}{\lambda^2},$$
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where $\mathrm{Var}$ denotes [[variance]].
<strong>Proof:</strong> █
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==Proof==
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==References==
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 14:06, 28 January 2023

Theorem

If $X$ with a random variable with the exponential distribution with parameter $\lambda$, then, $$\mathrm{Var}_{\mathbb{T}}(X)=\dfrac{1}{\lambda^2},$$ where $\mathrm{Var}$ denotes variance.

Proof

References