Difference between revisions of "Derivation of forward graininess for T=Harmonic numbers"
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(Created page with "$\begin{array}{ll} \mu(t) &= \mu \left( \displaystyle\sum_{k=1}^{n} \dfrac{1}{k} \right) \\ &= t + \dfrac{1}{n+1} - t \\ &= \dfrac{1}{n+1} \\ \end{array}$") |
(No difference)
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Latest revision as of 06:32, 16 June 2015
$\begin{array}{ll} \mu(t) &= \mu \left( \displaystyle\sum_{k=1}^{n} \dfrac{1}{k} \right) \\ &= t + \dfrac{1}{n+1} - t \\ &= \dfrac{1}{n+1} \\ \end{array}$
