Difference between revisions of "Delta derivative of unilateral convolution"
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Revision as of 13:41, 20 January 2023
Theorem
If $f$ is $\Delta$-differentiable, then $$(f*g)^{\Delta}=f^{\Delta}*g+f(t_0)g.$$ If $g$ is $\Delta$-differentiable, then $$(f*g)^{\Delta}=f*g^{\Delta}+fg(t_0).$$
