Relationship between nabla exponential and delta exponential
From timescalewiki
Theorem: If $p$ is continuous and $\nu$-regressive then $$\hat{e}_p(t,s)=e_{\frac{q^{\sigma}}{1-q^{\sigma}\nu}}(t,s)=e_{\ominus(-q^{\sigma})}(t,s),$$ where $\hat{e}$ denotes the $\nabla$-exponential and $e_p$ denotes the $\Delta$-exponential.
Proof: █
