Difference between revisions of "Unilateral convolution is associative"
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$$(f*g)*h = f*(g*h).$$ | $$(f*g)*h = f*(g*h).$$ | ||
Revision as of 13:42, 20 January 2023
Theorem
Unilateral convolution is associative, i.e. $$(f*g)*h = f*(g*h).$$
