Difference between revisions of "Covolution theorem for unilateral Laplace transform"
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Revision as of 13:37, 20 January 2023
Theorem
The following formula holds: $$\widehat{(f*g)}(t,s)=\displaystyle\int_s^t \hat{f}(t,\sigma(\xi))\hat{g}(\xi,s) \Delta \xi,$$ where $\widehat{(f*g)}$ denotes the solution of the shifting problem and $(f*g)$ denotes the convolution.