Difference between revisions of "Delta integral from t to sigma(t)"
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m (Tom moved page Integral from t to sigma(t) to Delta integral from t to sigma(t)) |
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Latest revision as of 22:40, 22 August 2016
Theorem
The following formula holds: $$\int_t^{\sigma(t)} f(\tau) \Delta \tau = \mu(t)f(t),$$ where $\int$ denotes the delta integral, $\sigma$ denotes the forward jump, and $\mu$ denotes the forward graininess.