Difference between revisions of "Unilateral Laplace transform of delta derivative"

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(Created page with "==Theorem== If $\mathbb{T}$ is a time scale, then $$\mathscr{L}_{\mathbb{T}}\{f^{\Delta}\}(z;s) = -f(s) + z\mathscr{L}\{f\}(z),$$ where $\mathscr{L}_{\mathbb{T}}$ denotes the...")
 
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==Proof==
 
==Proof==
Compute using integration by parts,
 
$$\begin{array}{ll}
 
\mathscr{L}\{f^{\Delta}\}(z) &= \displaystyle\int_0^{\infty} f^{\Delta}(\tau) e_{\ominus z}(\sigma(\tau),s) \Delta \tau \\
 
&=
 
\end{array}$$
 
proving the claim. █
 
  
 
==References==
 
==References==
  
 
[[Category:Theorem]]
 
[[Category:Theorem]]
[[Category:Proven]]
+
[[Category:Unproven]]

Revision as of 15:10, 21 January 2023

Theorem

If $\mathbb{T}$ is a time scale, then $$\mathscr{L}_{\mathbb{T}}\{f^{\Delta}\}(z;s) = -f(s) + z\mathscr{L}\{f\}(z),$$ where $\mathscr{L}_{\mathbb{T}}$ denotes the unilateral Laplace transform and $f^{\Delta}$ denotes the delta derivative of $f$.

Proof

References