View source for Relationship between delta exponential and nabla exponential

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<strong>[[Relationship between delta exponential and nabla exponential|Theorem]]:</strong> If $q$ is [[continuous]] and [[mu regressive | $\mu$-regressive]] then
$$e_q(t,s)=\hat{e}_{\frac{q^{\rho}}{1+q^{\rho}\nu}}(t,s)=\hat{e}_{\ominus_{\nu}(-q^{\rho})}(t,s),$$
where $e_q$ denotes the [[Delta exponential|$\Delta$-exponential]] and $\hat{e}_q$ denotes the [[nabla exponential|$\nabla$-exponential]].
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<strong>Proof:</strong> █ 
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