View source for Relationship between nabla exponential and delta exponential

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<strong>[[Relationship between nabla exponential and delta exponential|Theorem]]:</strong> If $p$ is [[continuous]] and $\nu$-regressive then
$$\hat{e}_p(t,s)=e_{\frac{q^{\sigma}}{1-q^{\sigma}\nu}}(t,s)=e_{\ominus(-q^{\sigma})}(t,s),$$
where $\hat{e}$ denotes the [[nabla exponential|$\nabla$-exponential]] and $e_p$ denotes the [[Delta exponential|$\Delta$-exponential]].
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<strong>Proof:</strong> █ 
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