Difference between revisions of "Integration by parts for delta integrals with sigma in integrand"
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(Created page with "==Theorem== The following formula holds: $$\int_a^b f(\sigma(t))g^{\Delta}(t) \Delta t = (fg)(b) - (fg)(a) - \int_a^b f^{\Delta}(t)g(t) \Delta t,$$ where $\int$ denotes the ...") |
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Revision as of 23:24, 22 August 2016
Theorem
The following formula holds: $$\int_a^b f(\sigma(t))g^{\Delta}(t) \Delta t = (fg)(b) - (fg)(a) - \int_a^b f^{\Delta}(t)g(t) \Delta t,$$ where $\int$ denotes the delta integral.
