# Difference between revisions of "Integration by parts for delta integrals with sigma in integrand"

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(Created page with "==Theorem== The following formula holds: $$\int_a^b f(\sigma(t))g^{\Delta}(t) \Delta t = (fg)(b) - (fg)(a) - \int_a^b f^{\Delta}(t)g(t) \Delta t,$$ where $\int$ denotes the ...") |
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==Proof== | ==Proof== | ||

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+ | [[Integration by parts for delta integrals with no sigma in integrand]]<br /> | ||

==References== | ==References== |

## Revision as of 14:47, 13 March 2018

## Contents

## Theorem

The following formula holds: $$\int_a^b f(\sigma(t))g^{\Delta}(t) \Delta t = (fg)(b) - (fg)(a) - \int_a^b f^{\Delta}(t)g(t) \Delta t,$$ where $\int$ denotes the delta integral.

## Proof

## See also

Integration by parts for delta integrals with no sigma in integrand