Difference between revisions of "Integration by parts for delta integrals with sigma in integrand"

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==Theorem==
 
==Theorem==
 
The following formula holds:
 
The following formula holds:

Latest revision as of 14:47, 13 March 2018

Theorem

The following formula holds: $$\int_a^b f(\sigma(t))g^{\Delta}(t) \Delta t = (fg)(b) - (fg)(a) - \int_a^b f^{\Delta}(t)g(t) \Delta t,$$ where $\int$ denotes the delta integral.

Proof

See also

Integration by parts for delta integrals with no sigma in integrand

References