# Delta integral from t to sigma(t)

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Revision as of 22:40, 22 August 2016 by Tom (talk | contribs) (Tom moved page Integral from t to sigma(t) to Delta integral from t to sigma(t))

## Theorem

The following formula holds: $$\int_t^{\sigma(t)} f(\tau) \Delta \tau = \mu(t)f(t),$$ where $\int$ denotes the delta integral, $\sigma$ denotes the forward jump, and $\mu$ denotes the forward graininess.