Difference between revisions of "Delta integral from t to sigma(t)"

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(Created page with "==Theorem== The following formula holds: $$\int_t^{\sigma(t)} f(\tau) \Delta \tau = \mu(t)f(t)$$ ==Proof== ==References== Category:Theorem Category:Unproven")
 
 
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==Theorem==
 
==Theorem==
 
The following formula holds:
 
The following formula holds:
$$\int_t^{\sigma(t)} f(\tau) \Delta \tau = \mu(t)f(t)$$
+
$$\int_t^{\sigma(t)} f(\tau) \Delta \tau = \mu(t)f(t),$$
 +
where $\int$ denotes the [[delta integral]], $\sigma$ denotes the [[forward jump]], and $\mu$ denotes the [[forward graininess]].
  
 
==Proof==
 
==Proof==

Latest revision as of 22:40, 22 August 2016

Theorem

The following formula holds: $$\int_t^{\sigma(t)} f(\tau) \Delta \tau = \mu(t)f(t),$$ where $\int$ denotes the delta integral, $\sigma$ denotes the forward jump, and $\mu$ denotes the forward graininess.

Proof

References